2x^2=36x+176

Solution for 2x^2=36x+176 equation:

2x^2=36x+176

We move all terms to the left:

2x^2-(36x+176)=0

We get rid of parentheses

2x^2-36x-176=0

a = 2; b = -36; c = -176;
Δ = b2-4ac
Δ = -362-4·2·(-176)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-52}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+52}{2*2}=\frac{88}{4}
=22
$